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A wheel whose moment of inertial is 0.03...

A wheel whose moment of inertial is `0.03kgm^(2)`, is accelerated from rest to `20rad//s` in 5 s. When the external torque is removed, the wheel stops in 1 min. Find
(a). The frictional torque.
(b). The external torque.

Text Solution

Verified by Experts

(a). Angular impulse
`=` change in angular momentum
`thereforetau_(f)t=Iomega`
or `tau_(f)=(Iomega)/(t)+tau_(f)=(0.03xx20)/(5)+0.01`
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