In backward slip condition translational kinetic energ of a disc may be equal to its rotational kinetic energy is this statement true of false?

Explanation

`K_(T)=(1)/(2)mv^(2),K_(R)=(1)/(2)=(1)/(2)Iomega^(2)=(1)/(2)((1)/(2)mR^(2))omega^(2)`
Since, in backward sli condition `vltRomega`
`thereforeK_(R)` may be equal to `K_(T)`.