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A mass m is at a distance a from one end...

A mass m is at a distance a from one end of a uniform rod of length l and mass M. Find the gravitational force on the mass due to tke rod.

Text Solution

Verified by Experts

The correct Answer is:
A, D

`dF=(G(dM)m)/(x^2)=(G((M)/(l)*dx)m)/(x^2)`

`:.F =int_(x=a)^(x=(a+l)) dF =(GMm)/(a(l+a)`
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Knowledge Check

  • A point mass is placed at a distance a from one end of a rod of mass M and length l on the line which passes through the central axis of the rod. The potential energy of the system.

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    ` U =- G M m ((1)/(a) - (1)/(a +1))`
    C
    `U=- ( GMm )/(1) log _(e) ((a + 1)/( a))`
    D
    `U =- ( GMm )/(a)`
  • In a street light of mass M is suspended from the end of a uniform rod of length L in different possible patterns as shown in figure, then :

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    pattern A is more sturdy
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  • In a street light of mass M is suspended from the end of a uniform rod of length L in different possible patterns as shown in figure, then :

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