Suppose the earth increases its speed of rotation . At what new time period will the weightof a body on the equator becomes zero? Take `g=10 m/s^2` and radius of the earth `R=6400 km`.

Answer

A, D

Explanation

The weight will become zero, when
`g'=0` or `g-R omega^(2)=0` (on the equater `g'=g-R omega^(2))`
or `omega=sqrt((g)/(R))`
`:.(2pi)/(T)=sqrt((g)/(R)) or T=2pisqrt((g)/(R))`
Substitution the values, `T=(2pi sqrt ((6400 xx 10^(3))/(10)))/(3600) h`
or `T = 1.4 h`
Thus, the new time period should e `1.4h` instead of `24h` for the weight of a dody to de zero on the equater .