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Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of the two particles.

Text Solution

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The correct Answer is:
A, B, C
`a_(1) = (F)/(m_(1)) = (Gm_(1)m_(2))/(r^(2)) = (Gm_(2))/(r^(2))`
`=((6.67 xx 10^(-11))(2))/((0.5)^(2))`
`= 5.3 xx 10^(-10) m//s^(2)`
Similarly, `a_(2) = (Gm_(1))/(r^(2))`
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