Three points A , B and C each of mass are placed in a line with AB=BC=d. Find the gravitational force on a fourth particle P of same mass placed at a distance d from the particle B on the perpendicular bisector of the line AC.

Answer

A, B, D

Explanation

`F_("net") = 2(F_(1) cos 45^(@)) + F_(2)`

`= sqrt(2) F_(1) + F_(2) = ((sqrt(2))Gmm)/((sqrt(2d))^(2)) + (Gmm)/(d^(2))`
`= ((sqrt(2) + 1)/(sqrt(2))) (Gm^(2))/(d^(2))` (Along PB)