The kinetic energy needed to project a body of mass m from the earth's surface to infinity is
Text Solution
Verified by Experts
`KE = (1)/(2) m nu_(e)^(2)` `= (1)/(2) m ((2 GM)/(R))` `= (m)/(R )(gR^(2))` (as `GM = gR^(2))` `= mgR`
Topper's Solved these Questions
GRAVITATION
DC PANDEY|Exercise Exercise 13.7|5 Videos
GRAVITATION
DC PANDEY|Exercise Level 1 Assertion And Reason|11 Videos
GRAVITATION
DC PANDEY|Exercise Exercise 13.5|6 Videos
GENERAL PHYSICS
DC PANDEY|Exercise INTEGER_TYPE|2 Videos
KINEMATICS
DC PANDEY|Exercise INTEGER_TYPE|11 Videos
Similar Questions
Explore conceptually related problems
The kinetic energy needed to project a body of mass m from the eath surface (radus R) to infinity is
The kinetic energy needed to project a body of mass m from the earth surface (radius R) to infinity is
The kinetic energy needed to project a body of mass m from the surface of the earth to infinity is
The energy required to remove a body of mass m from earth's surfac is/are equal to
What is the work done in shifting a body of mass m=5okg slowly from the earth's surface to infinity?
" The potential energy of a body of mass "m" on the surface of earth is "
The gravitational potential energy of body of mass 'm' at the earth's surface mgR_(e) . Its gravitational potential energy at a height R_(e) fromt the earth's surface will be (here R_(e) is the radius of the earth)
Knowledge Check
The kinetic energy needed to project a body of mass m from the eath surface (radus R) to infinity is
A
`mgR/2`
B
`2mgR`
C
`mgR`
D
`mgR/4`
The kinetic energy needed to project a body of mass m from the earth surface (radius R) to infinity is
A
`(mgR)/(2)`
B
`2mgR`
C
`mgR`
D
`(mgR)/(2)`
The kinetic energy needed to project a body of mass m from the surface of the earth to infinity is