If `M` is the mass of the earth and `R` its radius, the radio of the gravitational acceleration and the gravitational constant is

Options

A. `(R^(2))/(M)`
B. `(M)/(R^(2))`
C. `MR^(2)`
D. `(M)/(R)`

Answer

B

Explanation

`g = (GM)/(R^(2)) rArr :. (g)/(h) = (M)/(R^(2))`