If `upsilon_(e)` is the escape velocity for earth when a projectile is fired from the surface of earth. Then, the escape velocity if the same projectile is fired from its centre is

Options

A. `sqrt((3)/(2)) upsilon_(e)`
B. `(3)/(2) upsilon_(e)`
C. `sqrt((2)/(3)) upsilon_(e)`
D. `(2)/(3) upsilon_(e)`

Answer

A

Explanation

Potential (and hence potential energy) at centre is
`(3)/(2)` times velue on surface . So, required kinetic
energy is `(3)/(2)` times or required speed is `((3)/(2))` times.