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A particle starts from a point P at a di...

A particle starts from a point `P` at a distance of `A//2` from the mean position `O` and travels towards left as shown in the figure. If the time period of SHM, executed about `O` is `T` and amplitude `A` then the equation of the motion of particle is

A

`x = A sin ((2pi)/(T)t + (pi)/(6))`

B

`x = A sin((2pi)/(T)t + (5pi)/(6))`

C

`x = A cos ((2pi)/(T)t + (pi)/(6))`

D

`x = Acos ((2pi)/(T)t + (pi)/(3))`

Text Solution

Verified by Experts

The correct Answer is:
B, D
`x = Asin (omega t + 150^(@))`

` = A sin ((2pi)/(T)t + (5pi)/(6))`
or `x = Acos (omega t + 60^(@))`
`= A cos ((2pi)/(T)t + (pi)/(3))`
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