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The acceleration of a particle is a = - ...

The acceleration of a particle is `a = - 100x + 50`. It is released from `x = 2`. Here, `a` and `x` are in SI units

A

the particle will perform SHM of amplitude `2m`

B

the particle will perform SHM of amplitude `1.5 m`

C

the particle will perform SHM of time period `0.63 s`

D

the particle will have a maximum velocity of `15 m//s`

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
`a = 0` at `x = 0.5 m`
and particle is released from `x = 2m`
Hence, `A = 2 - 0.5`
`= 1.5 m`
`omega^(2) = 100`
`:. omega = 10 rad //s`
`T = (2pi)/(omega) = (2pi)/(10)`
`= 0.63 s`
`v_(max) = omega A = (10)(1.5)`
` = 15m//s`
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