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A U-tube of uniform cross-sectional area...

A U-tube of uniform cross-sectional area and open to the atmosphere is partially filled with mercury. Water is then poured into both arms. If the equilibrium configuration of the tube is as shown in figure with `h_(2)=1.0cm`, determine the value of `h_(1)`
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The correct Answer is:
A, B, C
`p_(1)=p_(2)`

` :. p_(0)+rho_(w)g (h_(1)+h_(2)+h)=p_(0)+rho_(w)gh+rho_(Hg)gh_(2)`
`:. h-1=((rho_(hg)-rho_(w))h_(2))/(rho_w)`
`=((13.6-1)(1.0))/(1)`
`=12.6 cm`.
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