A closed tube is filled with

`AB=2m`
`BC=4cm`
water `(rho=10^(3)kg//m^(3))`. It rotating about an axis shown in figure with an angular velocity `omega=2 rad//s`. Find, `p_(A)-p_(C)`.

Explanation

Pressure decreases in moving towards the axis of rotation and increases in moving away from the axis `(Delta p= +-(rho omega^(2)x^2)/(2))`
` :. p_(A)gtp_(B)` and `p_(B)gtp_(C)`
`p_(A)-p_(C)=(p_(A)-p_(B))+(p_(B)-p_(C))`
`=(+(rho omega^(2)x_(1)^(2))/(2))+((-rho omega^(2)x_(2)^(2))/(2))`
Here, `x_(1)=AB=2m`
and `x_(2)=BC=4m`
Substituting teh values we have,
`p_(A)-p_(C)=((10^(3))(2)^(2)(2)^(2))/(2)-((10^(3))(2)^(2)(4)^(2))/(2)`
`=-2.4xx10^(3) N//m^(2)`.