What should be the pressure inside a small air bubble of `0.1mm` radius situated just below the water surface. Surface tension of water `=7.2xx10^(-2)N//m` and atmosphere pressure`=1.013xx10^(5)N//m^(2)`.

Answer

A, B

Explanation

Surface tension of water `T=7.2xx10^(-2) N//m^(2)`
Radius of air bubble `R=0.1mm=10^(-4)m`
The excess pressure inside the air bubble is given by,
`p_(2)-p_(1)=(2T)/(R)`
`:.` Pressure inside the air bubble,
`p_(2)=p_(1)+(2T)/(R )`
Substituting the values, we have
`p_(2)=(1.013xx10^(5))+((2xx7.2xx10^(-2)))/(10^(-4))`
`=1.027xx10^(5) N//m^(2)`