A glass tube of radius `0.4mm` is dipped vertically in water. Find upto what height the water will rise in the capollary? If the tube in inclined at an angle of `60^(@)` with the vertical, how much length of the capillary is occupied by water? Suface of water`=7.0xx10^(-2)N//m`,density of water `=10^(3)kg//m^(3)`.

Answer

A, C, D

Explanation

For glass-water, angle of contact `theta=0^(@)`

Now, `h=(2T costheta)/(r rho g)`
`=((2)(7.0xx10^(-2))cos0^(@))/((0.4xx10^(-3))(10^(3))(9.8))`
`=3.57xx10^(-2)m=3.57cm`
`l=(h)/(cos 60^(@))=(3.57)/((1)/(2))=7.14 cm`