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The area of cross section of the wider t...

The area of cross section of the wider tube shown in figure is `900 cm^2`. If the boy standing on the piston weights 45 kg, find the difference in the levels of water in the two tubes.

Text Solution

Verified by Experts

The correct Answer is:
C
`Deltap_(1)=Deltap_(2)`
`(F)/(A)=(Delta h)(rho)g`
`:. (Delta h)=(F)/(A rho g)=(45g)/((900xx10^(-4))(10^(3)g))`
`=0.5m=50cm`.
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