Home
Class 11
PHYSICS
A small block of wood of density 0.4xx10...

A small block of wood of density `0.4xx10^(3)kg//m^(3)` is submerged in water at a depth of `2.9m`. Find
(a) the acceletation of the block towards the surface when the block is released and
(b) the time for the block to reach the surface, Ignore viscosity.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
(a) `a=("upthrust-weight")/(mass)`
`=((V)(1000)(9.8)-(V)(0.4xx10^(-3))(9.8))/((V)(0.4xx10^(3))`
`=14.7m//s^(2)`
(b) `t-sqrt((2s)/(a))`
`=sqrt((2xx2.9)/(14.7))`
`=0.63s`.
Promotional Banner

Topper's Solved these Questions

  • FLUID MECHANICS

    DC PANDEY|Exercise Exercise16.4|4 Videos

  • FLUID MECHANICS

    DC PANDEY|Exercise Exercise16.5|3 Videos

  • FLUID MECHANICS

    DC PANDEY|Exercise Exercise16.2|2 Videos

  • EXPERIMENTS

    DC PANDEY|Exercise Subjective|15 Videos

  • GENERAL PHYSICS

    DC PANDEY|Exercise INTEGER_TYPE|2 Videos

Similar Questions

Explore conceptually related problems

A small block of wood of relative density 0.5 is submerged in water at a depth of 5 m When the block is released it starts moving upwards, the acceleration of the block is (g=10ms^(-2) )

A small block of wood, of specific gravity 0.4 is submerged in water at a depth of 2.9 m. If the block is released from rest. Then choose the correct alternative(s).

A small block of wood of relative density 0.5 is submerged in water. When the block is released, it stats moving upwards, the acceleration of the block is (g=10 ms^(-2))

The R.D of a metal block is 2.7xx10^(3) kg//m^(3) . It is immersed in water. Then the block

Assuming all the surfaces to be smooth, find the acceleration of the triangular block of mass M when the block of mass m slides on it.

A block of wood floats with 3/4 th of its volume submerged in water. The density of wood is ________

A block of bras of mass 0.5 kg and density 8xx10^(3)kg//m^(3) is suspended from a string. What will be the tension in the string if the block is completely immersed in water? (g=10ms^(-2))

A block of mass m is placed on the inclined sufrace of a wedge as shown in fig. Calculate the acceleration of the wedge and the block when the block is released. Assume all surfaces are frictionless.

A block of material of specific gravity 0.4 is held submerged at a depth of 1m in a vessel filled with water. The vessel is accelerated upwards with acceleration of a_(o) = g//5 . If the block is released at t = 0, neglecting viscous effects, it will reach the water surface at t equal to (g = 10 m/s^(2)) :