A wave is described by the equation `y = (1.0 mm) sin pi((x)/(2.0 cm) - (t)/(0.01 s))`. (a) Find time period and wavelength. (b) Find the speed of particle at `x = 1.0 cm` and time `t = 0.01 s`. ( c ) What are the speed of the partcle at `x = 3.0 cm`, `5.0 cm and 7.0 cm` at `t = 0.01 s`? (d) What are the speeds of the partcle at `x =1.0 cm` at `t = 0.011` , `0.012 and 0.013 s`?
Text Solution
Verified by Experts
The correct Answer is:
A, B, C, D
(a) `T = (2pi)/(omega), lambda = (2pi)/(k)` (b) Find `(dely)/(delt)` and then substitute the given values of `x` and `t`. (c) and (d) Procedure is same.
Topper's Solved these Questions
WAVE MOTION
DC PANDEY|Exercise Exercise 17.3|4 Videos
WAVE MOTION
DC PANDEY|Exercise Exercise 17.4|2 Videos
WAVE MOTION
DC PANDEY|Exercise Exercise 17.1|4 Videos
VECTORS
DC PANDEY|Exercise Medical enrances gallery|9 Videos
WORK, ENERGY & POWER
DC PANDEY|Exercise Level 2 Comprehension Based|2 Videos
Similar Questions
Explore conceptually related problems
A wave is decribed by the equation y = (1.0mm) sin pi ((x)/(2.0cm) - (t)/(0.1s)). (a) Find the time period and the wavelength ? (b) Write the equation for the velocity of the particles. Find the speed of the particle at x = 1.0cm at time t = 0.01s, (c ) What are the speeds of the particles at x =3.0 cm 5.0 cm aned 7.0cm at t = 0.01 ? (d) What are the speeds of the particles at x = 1.0 cm at t= 0.011, 0.012, and 0.013s ?
A wave is represented by the equation y=(0.001mm)sin[(50s^-10t+(2.0m^-1)x]
A simple harmonic progressive wave is given by the equation, y = 0.1 sin 4 pi (50 t - 0.2 x) in SI units. Find the period, wavelength and speed of the wave.
A plate has a length ( 5pm 0.1 ) cm and breadth (2pm 0.01) cm . Then the area of the plate is
A wave is represented by the equation : y=a sin (0.01x-2t) where a and x are in cm . velocity of propagation of wave is
The equation of a travelling wave is y(x, t) = 0.02 sin ((x)/(0.05) + (t)/(0.01)) m Find (a) the wave velocity and (b) the particle velocity at x = 0.2 m and t = 0.3 s . Given cos theta = -0.85 , where theta = 34 rad
A certain transverse wave is described by y(x, t)=(6.50 mm) cos 2pi((x)/(28.0 cm) - (t)/(0.0360 s)). Determine the wave's (a) amplitude , (b) wavelength ( c ) frequency , (d) speed of propagation and (e) direction of propagation.
The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then the speed of the particle at 0.1 s will be
If A =12.0 cm pm 0.1 cm and B 8.5 cm pm 0.5 cm, find A + B
Along a stretched string equation of transverse wave is y = 3 sin [2pi ((x)/(20)-(t)/(0.01))] Where, x, y are in cm and t is in second. Calculate wave velocity.