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A harmonic oscillator vibrates with ampl...

A harmonic oscillator vibrates with amplitude of `4 cm` and performs `150` oscillations in minute. If intial phase is `45^(@)` and it starts moving away from the origin, then the equation of motion is

A

`0.04 sin ((5pit + (pi)/(4))`

B

`0.04 sin ((5pit - (pi)/(4))`

C

`0.04 sin ((4pit + (pi)/(4))`

D

`0.04 sin ((4pit - (pi)/(4))`

Text Solution

Verified by Experts

The correct Answer is:
A
`:' omega = (2pi)/(T) = (2pi)/((t//N)) = (2piN)/(t)`
`=((2pi)(150))/(60)`
`=(5pi) rad//s`
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