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An electric bulb of volume 250cc was sea...

An electric bulb of volume `250`cc was sealed during manufacturing at a pressure of `10^(-3)mm` of mercury at `27^(@)C`. Compute the number of air molecules contained in the bulb. Avogadro constant `=6xx10^(23)mol^(-1),` density of mercury`=13600kgm^(-3)` and `g=10ms^(-2)`.

Text Solution

Verified by Experts

The correct Answer is:
A
`pV = nRT`
`:. n = (p V)/(RT) = ((rho g h)V)/(RT)`
`= ((13.6 xx 10^3)(9.8)(10^-6)(250 xx 10^-6))/(8.31 xx 300)`
`= 1.33 xx 10^-8`
`:.` Number of molecules = `(n) N_A`
`= (1.33 xx 10^-8)(6.02 xx 10^23)`
`= 8 xx 10^15`.
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