One mole of an ideal monoatomic gas is initially at 300K. Find the final temperature if 200J of heat are added as follows:
(a) at constant volume (b) at constant pressure.

Answer

A, B, C

Explanation

(a) `Q=nC_VDeltaT=(1)(3/2R)(T_f-T_i)`
`:.` `200=1.5xx8.31(T_f-300)`
Solving we get,
`T_f=316K`
(b) `Q=nC_pDeltaT=(1)(5/2R)(T_f-T_i)`
`:.` `200=2.5xx8.31(T_f-300)`
`:.` `T_f~~310K`