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Five moles of an ideal monoatomic gas with an initial temperature of `127^@C` expand and in the process absorb 1200J of heat and do 2100J of work. What is the final temperature of the gas?

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The correct Answer is:
A, C

`DeltaU=Q-W=nC_VDeltaT=n(3/2R)(T_f-T_i)`
`:.` `1200-2100=5(3/2xx8.31)(T_f-400)`
`:.` `T_f=385K`
`~~113^@C`
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