Find the change in the internal energy of `2 kg` of water as it heated from `0^(0)C to 4^(0)C`. The specific heat capacity of water is `4200 J kg^(-1) K^(-1)` and its densities at `0^(0)C` and `4^(0)C` are `999.9 kg m^(-3)` and `1000 kg m^(-3)` respectively. atmospheric pressure `=10^(5)` Pa.

Answer

B, C

Explanation

`V_i=m/rho_i=2/999.9=2.0002xx10^(-3)m^(3)`
`V_f=m/rho_f=2/1000=2xx10^-3m^(3)`
`DeltaU=Q-W`
`=msDetlatheta-p_aDeltaV`
`=(2)(4200)(4)-(10)^5(-0.002xx10^-3)`
`=33600.2J`