Calculate the increase in the internal energy of `10 g` of water when it is heated from `0^(0)C to 100^(0)C` and converted into steam at `100 kPa`. The density of steam `=0.6 kg m^(-3)`, specific heat capacity of water `=4200 J kg^(-1 ^(0)C^(-3)` ,latent heat of vaporization of water `=2.25xx10 6 J kg^(-1)`

Answer

A, B, D

Explanation

`V_i=m/rho_i=0.01/1000=10^-5m^3`
`V_f=m/rho_f=0.01/0.6=0.0167m^3`
`DeltaU=Q-W`
`=msDeltatheta+mL-p_0DeltaV`
`=(0.01xx4200xx100)+(0.01)(2.5xx10)^6-10^5(0.0167-10^-5)`
`=27530J`