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A 1.0 kg bar of copper is heated at atmo...

A 1.0 kg bar of copper is heated at atmospheric pressure `(1.01xx10^5N//m^2)`. If its temperature increases from `20^@C` to `20^@C`, calculate the change in its internal energy. `alpha=7.0xx10^-6//^@C`, `rho=8.92xx10^3kg//m^3` and `c=387J//kg-^@C`.

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The correct Answer is:
A, B
`V=(m)/(rho)=(1.0)/(8.92xx10^3)`
`=1.12xx10^-4m^3`
`gamma=3alpha=2.1xx10^-5per^@C`
`DeltaV=VgammaDeltatheta`
`=(1.12xx10^-4)(2.1xx10^-5)(30)`
`=7.056xx10^-8m^3`
`W=pDeltaV`
`=(1.01xx10^5)(7.056xx10^-8)`
`=7.13xx10^-3J`
`Q=mcDeltaQ`
=(1)(387)(30)`
`Delta U=Q-W`
`=11609.99287J`
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