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A conducnting straight wire PQ of length...

A conducnting straight wire `PQ` of length `l` is fixed along as diameter of a non conducting ring as shown in the figure. The ring is given a pure rolling motion on as horizontal masgnetic field `B` in horizontal direction perpendicular to the plane of ring. The magnitude of induced emf in the wire PQ at the position shown in figure will be

A

`2 BvR`

B

`1/2BvR`

C

`8 BvR`

D

`4BvR`

Text Solution

Verified by Experts

The correct Answer is:
D

`PD=(Bomegal^2)/2=((B)(v//2R)(4R)^2)/2=4BvR`
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