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When a choke coil carrying a steady curr...

When a choke coil carrying a steady current is short circuited, the current in it decreases to `beta(lt1)` times its initial value in a time `T`. The time constant of the choke coil is

A

`T/beta`

B

`T/(ln(1/beta)`

C

`T/(lnbeta)`

D

`T ln beta`

Text Solution

Verified by Experts

The correct Answer is:
B
`i=i_0e^(-t//tau_L)`
`betai_0=i_0e^(-t//tau_L)`
`:. tau_L=T/(ln(1//beta))`
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