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In the figure, magnetic field points int...

In the figure, magnetic field points into the pane of paper and the conducting rod of length `l` is moving in this field such that the lowest point has a velocity `v_1` and the topmost point has the velocity `v_2(v_2gtv_1)`. The emf induced is given by

A

`Bv_1l`

B

`Bv_2l`

C

`1/2B(v_2+v_1)l`

D

`1/2BI(v_2-v_1)l`

Text Solution

Verified by Experts

The correct Answer is:
C

`v=v_1+((v_2-v_1)/l)x`
Small potential difference `=Bv(dx)`
`:.` Total potential difference `=int_0^1Bvdx`
`=1/2B(v_1+v_2)l`
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