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Find the current passing through battery...

Find the current passing through battery immediately after key `(K)` is closed. It is given that initially all the capacitors are uncharged. (Given that `R=6Omega` and `C=4muF)`

A

`1A`

B

`5A`

C

`3A`

D

`2A`

Text Solution

Verified by Experts

The correct Answer is:
A

At time `t=0`, resistance offered by a capacitor `=0` and resistance offered by an inductor `=alpha`
`R_("net")=R/2+R/3=(5R)/6=5Omega`
`:.` Current from the battery,
`i=E/R_("net")=5/5=1A`
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