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An AC circuit consists of a 220Omega res...

An `AC` circuit consists of a `220Omega` resistance andn a `0.7 H` choke. Find the power obsorbed from `220 V` and `50 Hz` source connected in this circuti if the resistance and choke are joined
(a) In series
(b) in parallel.

Text Solution

Verified by Experts


(a) In sereies, the impedance of the circuit is
`Z=sqrt(R^2+omega^2L^2)=sqrt(R^2+(2pi/L)^2)`
`=sqrt((220)^2+(2xx3.14xx50xx0.7)^2)`
`=311Omega`
`:. i_("rms")=V_("rms")/Z=220/311=0.707A`
and `cosphi=R/Z=220/311=0.707`
`:.` the power absorbed in the circuit
`P=V_("rms")i_("rms")cosphi`
`=(220)(0.707)(0.707)`
`=110.08W`
(b) When the resistance and choke are in parallel, the entire power is absorbed in resistance, as the choke (having zero resistance) absorbs no power.
`P=V_("rms")^2/R=((220)^2)/220=220W`.
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Knowledge Check

  • An AC circuit consists of a resistance and a choke coil in series . The resistance is of 220 Omega and choke coils is of 0.7 H . The power abosorbed from 220 V and 50 Hz , source connected with the circuit , is

    A
    55 W
    B
    110 W
    C
    220 W
    D
    440 W

  • A 0.21 H inductor and a 12 Omega resistance are connected in series to a 220 V, 50 Hz ac source. The current in the circuit is

    A
    `(220)/(sqrt(4400))A`
    B
    `(22)/(3sqrt(5)) A`
    C
    `(220)/(sqrt(4500))A`
    D
    `(22)/(5sqrt(3)) A`

  • A 0.2 k Omega resistor and 15 mu F capacitor are connected in series to a 220 V, 50 Hz ac source. The impadance of the circuit is

    A
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