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An AC circuit consists of a 220Omega res...

An `AC` circuit consists of a `220Omega` resistance andn a `0.7 H` choke. Find the power obsorbed from `220 V` and `50 Hz` source connected in this circuti if the resistance and choke are joined
(a) In series
(b) in parallel.

Text Solution

Verified by Experts


(a) In sereies, the impedance of the circuit is
`Z=sqrt(R^2+omega^2L^2)=sqrt(R^2+(2pi/L)^2)`
`=sqrt((220)^2+(2xx3.14xx50xx0.7)^2)`
`=311Omega`
`:. i_("rms")=V_("rms")/Z=220/311=0.707A`
and `cosphi=R/Z=220/311=0.707`
`:.` the power absorbed in the circuit
`P=V_("rms")i_("rms")cosphi`
`=(220)(0.707)(0.707)`
`=110.08W`
(b) When the resistance and choke are in parallel, the entire power is absorbed in resistance, as the choke (having zero resistance) absorbs no power.
`P=V_("rms")^2/R=((220)^2)/220=220W`.
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Knowledge Check

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