Home
Class 12
PHYSICS
Two coherent sources of intensity ratio ...

Two coherent sources of intensity ratio ` beta^2` interfere. Then, the value of `(I_(max)- I_(min))//(I_(max)+I_(min))` is

A

`(1+beta)/(sqrt beta)`

B

`(sqrt(1+beta)/beta)`

C

`(1+beta)/beta`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
`I_1/I_2 =beta^2`
So let, `I_2 = 1unit, then I_1=beta`
`I_(max) = (sqrtI_1+sqrtI_2)^2 = (I+beta)^2`
`I_(min) = (sqrtI_1+sqrtI_2)^2 = (I+beta)^2`
`= I_(max) - I_(min) =4beta`
` I_(max) + I_(min) = 2(1+beta^2)`
:. The asked ratio is `(2beta)/(1+beta^2).`
Promotional Banner

Topper's Solved these Questions

  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY|Exercise Objective question|2 Videos

  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY|Exercise Level 1Subjective|22 Videos

  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY|Exercise Level 1 Assertion And Reason|10 Videos

  • GRAVITATION

    DC PANDEY|Exercise All Questions|120 Videos

  • MAGNETIC FIELD AND FORCES

    DC PANDEY|Exercise Medical entrance s gallery|59 Videos

Similar Questions

Explore conceptually related problems

The interference pattern is obtained with two coherent light sources of intensity ratio n. In the interference patten, the ratio (I_(max)-I_(min))/(I_(max)+I_(min)) will be

Two coherent sources of intensity ratio alpha interfere. In interference pattern (I_(max)-I_("min"))/(I_(max)-I_("min")) =

Two doherent sources of intensity ratio alpha interfere in interference pattern (I_(max)-I_(min))/(I_(max)+I_(min)) is equal to

Two coherent sources with intensity ratio alpha interfere. Then, the ratio (l_(max)-l_("min"))/(l_(max)+l_("min")) is

Two coherent sources of intensity ratio beta interfere, then (I_(max)-I_(min))/(I_(max)+I_(min)) is

Two coherent sources of intensity ratio alpha interface . In interference pattern (I_("max") - I_("min"))/(I_("max") + I_("min")) =