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The ratio of maximum to minimum intensit...

The ratio of maximum to minimum intensity due to superposition of two waves is `49/9`. Then, the ratio of the intensity of component waves is.

A

25/4

B

`5/4

C

25/6

D

7/5`

Text Solution

Verified by Experts

The correct Answer is:
A
`I_(max)/I_(min) = (sqrt(I_1//I_2)+1)^2/(sqrt(I_1//I_2)-1)^2 = 49/9`
Solving, we get `I_1/I_2 = 25/4`.
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