in order that the short wavelength limit of the continuous X-ray spectrum be `1 Å`, the potential difference through which an electron must be accelerated is

Options

A. 124 kV
B. 1.24 kV
C. 12.4 kV
D. 1240 kV

Answer

C

Explanation

`lambda_(min) (in Å) = (12375)/(V(in volts)`
For `lambda_(min) = 1Å`
V = 12375 V
`~~12.4 kV.`