if the electron in hydrogen orbit jumps form third orbit to second orbit, the wavelength of the emitted radiation is given by

Options

A. `lambda = (R )/(6)`
B. `lambda = (R )/(6)`
C. `lambda = (36)/(5R)`
D. `lambda = (5R)/(36)`

Answer

C

Explanation

`(1)/(lambda) = R((1)/(n_1^2) -(1)/(n_2^2)) = R ((1)/(4) - (1)/(9)) = (5R)/(36)`
`:. Lambda = (36)/(5R).`