Home
Class 12
PHYSICS
The magnetic needle of a tangent galvano...

The magnetic needle of a tangent galvanometer is deflected at an angle `30^(@)` due to a magnet. The hoeizontal component of earth's magnetic field `0.34xx10^(-4)T` is along the plane of the coil. The magnetic intensity is

A

`1.96 xx 10^(-4)T`

B

`1.96xx10^(4)T`

C

`1.96 xx 10^(-5)T `

D

`1.96 xx 10^(5)T`

Text Solution

Verified by Experts

The correct Answer is:
C

Angle through which magnet is deflected `(theta)= 30^(@)` and horizontal magnetic field `(B_(R))=0.34xx 10^(-4)T` . Magnetic intensity `=B_(R) tan theta = 0.34 xx 10^(-4) xx tan 30^(@) =(0.34 xx 10^(-4)) xx 0.577 =1.96 xx 10^(-5) T `.
Promotional Banner

Topper's Solved these Questions

  • AIIMS 2001

    AIIMS PREVIOUS YEAR PAPERS|Exercise PHYSICS|60 Videos
  • AIIMS 2003

    AIIMS PREVIOUS YEAR PAPERS|Exercise PHYSICS|60 Videos

Similar Questions

Explore conceptually related problems

The magnetic needle of a tangent galvanometer is deflected at an angle of 30^@ due to magnet. The horizontal component of earth's magnetic field 0*34xx10^-4T is along the plane of the coil. What is magnetic intensity?

The angle of dip at a certain place is 30^(@) . If the horizontal component of the earth's magnetic field is H, the intensity of the total magnetic field is

The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@ . Find the magnitude of the earth's magnetic field.

At certain place, the horizontal component of earth's magnetic field is 3.0G and the angle dip at the place is 30^(@) . The magnetic field of earth at that location

The horizontal component of the earth's magnetic field is 0.22 Gauss and total magnetic field is 0.4 Gauss. The angle of dip. Is

At a certain place the angle of dip is 30^(@) and the horizontal component of earth's magnetic field is 0.50 oersted. The earth's total magnetic field is

A tangent galvanometer has a coil of 25 turns and radius of 15 cm. The horizontal component of the earth's magnetic field is 3xx10^(-5)T . The current required to producea defection of 45^(@) in it, is

A tangent galvanometer has a coil of 50 turns and a radius of 20cm. The horizontal component of the earth's magnetic field is B_H = 3 xx 10^(-5) T . Find the current which gives a diflection of 45^) .

AIIMS PREVIOUS YEAR PAPERS-AIIMS 2002-PHYSICS
  1. In the given figure the capacitors C(1), C(3), C(4),C(5) have a capaci...

    Text Solution

    |

  2. An electric bulb, marked 40 W and 200 V, is used in a circuit of suppl...

    Text Solution

    |

  3. The magnetic needle of a tangent galvanometer is deflected at an angle...

    Text Solution

    |

  4. The coefficient of mutual inductance when magnetic flux change by 2xx1...

    Text Solution

    |

  5. Light propagates rectilinearly because of its

    Text Solution

    |

  6. Brilliance of diamond is due to

    Text Solution

    |

  7. Velocity of light is equal to

    Text Solution

    |

  8. The Cauchy's formula is

    Text Solution

    |

  9. Golden view of sea shell is due to

    Text Solution

    |

  10. At the appermost point of a projectile its velocity and acceleration ...

    Text Solution

    |

  11. The kinetic energy of a body becomes four times its initial value.The ...

    Text Solution

    |

  12. The angular momentum of a moving body remains constant if

    Text Solution

    |

  13. The force of gravitation is

    Text Solution

    |

  14. Kepler's second law is based on

    Text Solution

    |

  15. A conducting sphere of radius 10 cm is charged 10 muC. Another uncharg...

    Text Solution

    |

  16. What is the path difference of destructive interference

    Text Solution

    |

  17. A siren emitting sound of frequency 800 Hz is going away from a sta...

    Text Solution

    |

  18. A string in a musical instrument is 50 cm long and its fundamental fr...

    Text Solution

    |

  19. The equation of a sound wave is y=0.0015sin(62.4x+316t) the wavelength...

    Text Solution

    |

  20. The graph between wave number (vecv) and angular frequency (omega) is

    Text Solution

    |