Two spring are connected toa block of mass `M` placed a frictionless surface as shown if both the spring have a spring constant `k` the frequency of oscillation block is

Options

A. `(1)/(2pi)sqrt((k)/(M)`
B. `(1)/(2pi)sqrt((k)/2M)`
C. `(1)/(2pi)sqrt((2k)/(M)`
D. `(1)/(2pi)sqrt((M)/(K))`

Answer

B

Explanation

The spring constant of spring connected in series is equal to
`k=(k_(1)k_(2))/((k_(1)+k_(2))-(k)/(2)`
Thus frequency of oscillation of given system is
`f=(1)/(2pi)sqrt((k)/(2m))`