`A 40 muF` capacitor in a defibrillator is charged to `3000 V`. The energy stored in the capacitor is sent through the patient during a pulse of duration `2 ms`. The power delivered to the patient is

Options

A. 45KW
B. 90KW
C. 180KW
D. 360KW

Answer

B

Explanation

The energy stored in capicitor`=(1)/(2)CV^(2)`
`=(1)/(2)xx40xx10^(-6)=180 J`.
`=20xx9xx10^(6)xx10^(-6)=180 J`.
The power delivered in 2 ms is
`=(180)/(2xx10^(-3))=90xx10^(3)` W=90 kW.