Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimension of permittivity is:

Options

A. `ML^(-2)T^(2)A`
B. `M^(-1)L^(-3)T^(4)A2^(2)`
C. `MLT^(-2)A`
D. `ML^(2)T^(-1)A^(2)`

Answer

B

Explanation

Force of attraction between two charges is given by
`F=(1)/(4piepsi_(0))(q_(1)q_(2))/(r^(2)`
`epsi_(0)=(1)/(4pi)(1)/(F)(q_(1)q_(2))/(r^(2))=(A^(2)T^(2))/(MLT^(-2)L^(2)`
(where `4pi` is dimensionless)ltbrge`M^(-1)L^(-3)T^(4)A^(2)`.