When `10 ml` of `0.1 M` acitec acid `(pk_(a)=5.0)` is titrated against `10 ml` of `0.1M` ammonia solution `(pk_(b)=5.0)`,the equivalence point occurs at `pH`

Options

A. `5.0`
B. `6.0`
C. `7.0`
D. `9.0`

Answer

C

Explanation

`pK_(a)=-logK_(a)pK_(b)=-logK_(b)`
`pil=-(1)/(2)[log K_(a)+log K_(w)-log K_(h)]`
`=(1)/(2)[-5+log (1xx10^(-14))-(-5)]`
`=-(1)/(2)[-5-14+5]=-(1)/(2)(-14)=7`.