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A uniform string is vibrating with a fun...

A uniform string is vibrating with a fundamental frequency 'f'. The new frequency, if radius & length both are doubled would be

A

2f

B

3f

C

`f/4`

D

`f/3`

Text Solution

Verified by Experts

The correct Answer is:
C

Fundamental frequency of a vibrating string is expressed as
` f = ( 1 )/ ( 2 L ) sqrt (( T ) / ( mu ) ) = ( 1 ) /( LD) sqrt ((T ) /( pi rho ) ) `
Where , D = diameter of string
` rho ` = density of the material of string
As length L and radius are doubled, the new frequency
` f ' = ( 1 ) /( (2L ) ( 2D) ) sqrt ((T ) /(pi rho )) = ( 1 ) /( 4 ) f `
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