A capillary tube of radius r is immersed in water and water rises in to a height h. The mass of water in the capillary tube is 5g. Another capillary tube of radius 2 r is immersed in water. The mass of water that will rise in this tube is

Options

A. 2.5 g
B. 5.0 g
C. 10 g
D. 20 g

Answer

C

Explanation

`h=(2S cos theta)/(rpg)`
Mass of water in the first tube.
`m=pir^2h=pir^(2)xx((2S cos theta)/(rpg))xxp`
`=(2pi S cos theta)/(g)`
`therefore m alpha r. "Hence " (m)/(m)=(2r)/(r)=2`
`or m'=2m=2xx5g=10g`