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Out of the following pairs, which one do...

Out of the following pairs, which one does not have identical dimensions?

A

impulse and momentum

B

moment of inertia and moment of force

C

angular momentum and Planck's constant

D

work and torque.

Text Solution

Verified by Experts

The correct Answer is:
B

Impulse `=Fxxt`
`=(m(v_(2)-v_1))/(t)xxt=m(v_(2)-v_(1))`
=change in momentum
`therefore` [Impulse]=[Momentum]
Planck's constant, [h]=`["energy"]xx ["time"]`
`Rightarrow [Fxxr xx "time"]=(m(v_2-v_1))/(t)xxrxxt`
`Rightarrow m(v_(2)-v_(1))xxr=("change of momentum")xxr` `therefore [h]=[l]`
Work, `W=vecF.vecd."Torque","tau=vecrxxvecF`
`therefore [W]=[tau]`
Moment of inertia `l=mr^(2)="mass " xx ("distance")^(2)`
Moment of force `,tau=vecr xx vec F="distance" xx "force"` `="distance "xx ("change in momentum")/("time")`
`therefore [1] ne [tau]`
Therefore, moment of inertia and moment of force have different dimensions.
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