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If current in diode is five times that i...

If current in diode is five times that in `R_(1).` Breakdown voltage of diode is 6 volt. Find R= ?

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Current in zero diode is 5 times.
So total current drawn from battery `=6 mA+30 mA=36 mA`
Potential difference Across `R=24` volt
So V= IR `24=36xx10^(-3)R,R=2000//3 Omega`
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