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Range of the ammeter is 5 ampere and ful...

Range of the ammeter is 5 ampere and full scale diflection current is `0.5 muA.` If resistance of galvanomenter is `50 Omega` then find shurt resistance.

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`S=(I_(g)G)/(1-I_(g))`
`S=(5xx10^(-7)xx50)/(5-(5xx10^(-7)))=5xx10^(-6)Omega`
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