A satellite which is revolving around earth has minimum distance from earth equal to `r_(1)` and maximum distance equal to `r_(2)` then time period of the satellite will be ?

Explanation

`2a=r_(1)+r_(2)`
`T=(2pi(a)^(3//2))/(sqrt(Gm))`
`T=(2pi((r_(1)+r_(2))/(2))^(3//2))/(sqrt(Gm))`