In the reaction given in euaqution 8, mention:
I. Which reactant is oxidised? To what?
II. Which reactant is the oxidiser?
III.Which reactant is reduced? To what?
IV. What reactant is the reducer?

Answer

A

Explanation

I. Zince metal is oxidised to (II) `Zn^(2+), Pb^(2+)` is the oxidiser. (III) `Pb^(2+)` is reduced to `Pb`,(IV) `Zn` is the reducer.
b. `I^(ө)` is oxidised to `I_(2),Fe^(3+)` is oxidiser
`Fe^(3+)` is reduced to `Fe^(2+), I^(-)` is the reducer.
c. `Na` is oxidised to `na^(+), Cl_(2)` is the oxidiser.
`Cl_(2)` is reduced to `Cl^(ө),Na` is the reducer.
d. `Mg` is oxidised to `Mg^(+2), Cl_(2)` is the oxidiser.
`Cl_(2)` is reduced to `Cl^(ө), Mg` is the reducer.
e. `Zn` is oxidised to `Zn^(2+), H^(o+)` is the reducer.
`H^(o+)` is reduced to `H_(2), Zn` is the reducer.