In question `10`, state which element is oxidised by which element and what is reduced to what in the reactions expressed by the respective equaitons.

Answer

A

Explanation

a. `Fe^(3+)` is reduced to `Fe^(2+)` and `H_(2)S` is oxidised to `S`.
b. `I^(ө)` is oxidised to `I_(2)` and `H^(o+)` is reduced to `H_(2)O`.
c. `Bi` is oxidised to `Bi^(3+)` and `H^(o+)` is reduced to `H_(2)O`.
d. `I^(ө)` is oxidised to `I_(2)`, and `O_(2)` and `H_(2)O` are reduced to `overset(ө)OH`.
e. `Au^(o+)` is reduced to `Au` and `Cu`d is oxidised to `cu^(2+)`.