0.1 " mol of "`MnO_(4)^(ɵ)` (in acidic medium) can:

Options

A. Oxidise 0.5 " mol of "`Fe^(2+)`
B. Oxidise 0.166 " mol of "`FeC_(2)O_(4)`
C. Oxidise 0.25 " mol of "`C_(2)O_(4)^(2-)`
D. Oxidise 0.6 " mol of "`Cr_(2)O_(7)^(2-)`

Answer

A, B, C

Explanation

(a). `MnO_(4)^(ɵ)+8H^(o+)+5e^(-)toMn^(2-)+4H_(2)O`
`m" Eq of "MnO_(4)^(ɵ)=0.1xx5=0.5`
`Fe^(2+)toFe^(3+)+e^(-)`
`impliesm" Eq of "Fe^(2+)=0.5`
(b). `FeC_(2)O_(4)toFe^(3+)+2CO_(2)+3e^(-)`
`implies m" Eq of "FeC_(2)O_(4)=0.166xx3=0.5`
(d). `Cr_(2)O_(7)^(2-)` being an oxidising agent cannot be oxidised