A compound contains three elements `A,B` and `C`, if the oxidation number of `A=+2B=+5` and `C=-2` then possible formula of the compound is

Options

A. `A(BC_(3))_(2)`
B. `A_(3)(BC_(4))_(2)`
C. `A_(3)(B_(4)C)_(2)`
D. `ABC_(2)`

Answer

A, B

Explanation

The possible formula be `A_(x)B_(y)C_(z)`.
As compound is neutral, so `x(+2)+y(+5)+z(-2)=0`
`implies2x+5y-2z=0`
By hit and trial we get : `x=1,y=2,z=6` and `x=3,y=2,z=8`
So compound is `A(BC_(3))_(2) or A_(3)(BC_(4))_(2)`