Choose the correct statement:

Options

A. 1 " mol of "`MnO_(4)^(ɵ)` ion can oxidise 5 " mol of "`Fe^(2+)` ion in acidic medium.
B. 1 " mol of "`Cr_(2)O_(7)^(2-)` ion can oxidise 6 " mol of "`Fe^(2+)` ion in acidic medium.
C. 1 " mol of "`Cu_(2)S` can be oxidised by 1.6 mole of `MnO_(4)^(ɵ)` ion in acidic medium.
D. 1 " mol of "CuS can be oxidised by 1 " mol of "`Cr_(2)O_(7)^(2-)` ion in acidic medium.

Answer

A, B, C, D

Explanation

(a). `m" Eq of "Fe^(2+)=1xx5=5`
`m" Eq of "MnO_(4)^(ɵ)=1xx5=5`
(b). `Cr_(2)O_(7)^(2-)+6Fe^(2+)+14H^(o+)to2Cr_(3+)+7H_(2)O+6Fe^(3+)`
`1 " mol of "Cr_(2)O_(7)^(2-)-=6 mol Fe^(2+)`
(c). Find n factor of `Cu_(2)S`
`Cu_(2)^(2+)to2Cu^(2+)+2e^(-)`
`underlineS^(2-)tooverset(+4)(SO_(2))+6e^(-))`
`underline(1 mol Cu_(2)S-=8 mol e^(-))`
`impliesm" Eq of "Cu_(2)S=1xx8=8`
Now m" Eq of "`MnO_(4)^(ɵ)` (acidic) `=5xx1.6=8`
(d). `Cr^(2+)toCu^(2+)` (not a redox reaction)
`S^(2-)toSO_(2)+6e^(-)`
`implies1 mol CuS-=6mole^(-)`
`implies n-"factor" of Cus=6`
`m" Eq of "CuS=1xx6=6`
`m" Eq of "Cr_(2)O_(7)^(2-)=1xx6=6`